x^2+0.713x=0.252

Solution for x^2+0.713x=0.252 equation:

x^2+0.713x=0.252

We move all terms to the left:

x^2+0.713x-(0.252)=0

We add all the numbers together, and all the variables

x^2+0.713x-0.252=0

a = 1; b = 0.713; c = -0.252;
Δ = b2-4ac
Δ = 0.7132-4·1·(-0.252)
Δ = 1.516369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.713)-\sqrt{1.516369}}{2*1}=\frac{-0.713-\sqrt{1.516369}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.713)+\sqrt{1.516369}}{2*1}=\frac{-0.713+\sqrt{1.516369}}{2}
$